Question

a number is increased by 20% and then the increased number is decreased by 20% find the net increase or decrease percent ​

Answer 1

Answer:

A number is increased by 20% and then decreased by 20%. What is the net increase or decrease percent?

The answer is 4% .

Let the number be x.

1st step : It is increasedd by 20% .

Amount if increase = (20/100)*x

THerefore,the number now after increase = Previous value+amount increased

=x+(20/100)*x =(120/100) *x

2nd step: The resultant number is again decreased by 20% .

Amount decreased= (20/100)*(120/100)*x = 24x/100

The number now = (120/100) x- (24/100)x =96x/100

Now the original number was x and now it is 96x/100.

so net decrease = x-96x/100

Percentage decrease =(net decrease/ original value)* 100

=4%

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Answer 2

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• Let the Number be 100.

➟ 100 × (100 + 20)% × (100 - 20)%

➟ 100 × 120% × 80%

➟ 100 × $\large\tt{\frac{120}{100}}$ × $\large\tt{\frac{80}{100}}$

➟ 100 × $\large\tt{\frac{12}{10}}$× $\large\tt{\frac{8}{10}}$

➟ 1 × 12 × 8

➟ 96%