Question

A number is increased by 20%. By what per cent the new number is decreased
so that the number restores the original value? ​

Answer 1

Answer:

The new number should be decreased by 16.66% to restore it to the original number.

Step-by-step explanation:

Let the old number be = x

the new number = x + 20% of x = x + 20x/100

= 120x/100 = 6x/5

the the number should be decrease by

6x/5 - x =(6x - 5x) / 5 = x/5

% decrease = (x/5) / 120x * 100 = x/600x *

100 = 1/6 = 16.66%

I hope it helps you.

Answer 2

Answer:

16.66 answer is correct