Question

A number is increased by 20% by what percent the new number is decreased so that the numbers restore the original value

Answer 1

Answer:

Let the old number be = x

New number = x + 20% of x

= x + 20x/100

= 120x/100

= 6x/5

The number should be decreased by 6x/5 - x

= (6x-5x) / 5 = x/5

% decease

= (x/5) / 120x * 100

= x/600x * 100

= 1/6

= 16.66%

The new number should be decreased by 16.66% to restore it to the original number.

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Answer 2

Answer:

here is your answer

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