Question

A number is increased by 20%. By what percentage the number must be decreased to get original number?

Answer 1

Keep the first number as x

So the new number = x + 20% of x  = x + $\frac{20x}{100}$ = $\frac{120x}{100}$ = $\frac{6x}{5}$

The number should be decreased by $\frac{6x}{5}$ - x = $\frac{(6x-5x)}{5}$ = $\frac{x}{5}$

Percentage decreased = $\frac{x}{5}$ ÷ 120x × 100 = $\frac{x}{600x}$ × 100 = $\frac{1}{6}$ = 16.66%

∴ The new number should be decreased by 16.66% to obtain the original number.

Hope this helps.

Answer 2

Answer:120/100

20/120×100=50/3

Step-by-step explanation: