Question

a number is increased by 5% and then the increased number is decreased by 5% find the net increase or decrease percent​

Answer 1

Answer:

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Step-by-step explanation:

Answer is in the attachment.

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Answer 2

Answer:

The number will decrease by 0.25%.

Step-by-step explanation:

Suppose the number is 'x'.

• Step-1: x is increased by 5%. So the increase = $\frac{5x}{100}$ = $\frac{x}{20}$

        After increasing, the increased value = x + $\frac{x}{20}$ = $\frac{21x}{20}$

• Step-2: Now decreasing is done on the increased value. That means 5% will decrease on  $\frac{21x}{20}$.

       Decrease amount =  $\frac{21x}{20}$ × $\frac{5}{100}$ = $\frac{21x}{400}$

       After decreasing  the number will become = $\frac{21x}{20}$ -  $\frac{21x}{400}$  = $\frac{21x\times19}{400}$

                                                                                                = 0.9975x

• Percentage calculation: The initial number was = x

                                                  Finally the number becomes = 0.9975x

                                          Number decreased by x - 0.9975x =0.0025x

       Decrease percentage = $\frac{0.0025x}{x}$ × 100% = 0.25%

    ∴ The number will decrease by 0.25%.

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