A number is multiplied by 7/3 times itself and then 61 is subtracted from the product obtained. If the final result is 9200, then the number is -------?
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Let the number be 'n' , then according to the given condition we get the equation as follows
=> (n)*(7/3)n - 61 = 9200
Now , multiplying both sides by 3 , we get
=> 7n^2 - 61*3 = 9200*3
=> 7n^2 - 183 = 27600
=> 7n^2 = 27783
=> n^2 = 3969
Taking square root on both sides
=> n =63
So , the required number is 63
=> (n)*(7/3)n - 61 = 9200
Now , multiplying both sides by 3 , we get
=> 7n^2 - 61*3 = 9200*3
=> 7n^2 - 183 = 27600
=> 7n^2 = 27783
=> n^2 = 3969
Taking square root on both sides
=> n =63
So , the required number is 63
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