Question

A number is of 2 digits. The sum and the difference of that number and that formed by reversing the digits are 99 and 45 respectively. Find the numbers​

Answer 1

solution

let the digit in one's place is =X

and the digit in ten's place is =y

now .actual number is =10y+x

and reversed number is =10x+y

now..

condition 1

(10y+x)+(10x+y)=99

=>11y+11x=99

=>x+y=9........(I)

now...

condition 2

(10y+x)-(10x+y)=45

=>9y-9x=45

=>y-x=5.......(ii)

now... solving 1 and 2 equations....

y=7 and x=2

therefore the actual number is

=10(7)+2=72

Hope this helps you ✌️✌️✌️✌️

Answer 2

Answer:

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