Question

a number is selected at random from 50 natural numbers. find the probability that it is a multiple of 3 and 4​

Answer 1

Let s be the sample space

n(s)=50

Let A be the event that the number drawn is a .multiple of 3 and 4

A={3,6,9,12,15,18,21,24,27,30,33,36,39,42,45,48,4,8,16,20,28,32,40,44}

n(A)=24

p(A)= n(A)/n(s)

= 24/50

=12/25

Therefore,the probability that the number selected randomly from 50 natural numbers is a multiple of 3 and 4 is12/25.

Hope it helps u ^_^ ^_^ ^_^

plzz mark it as brainliest

X________X

Answer 2

Answer:

Step-by-step explanation:

A mutiple of 3 and 4 is also a mutiple of 12. So out of 50 natural numbers we can find [50/12] integers that are a multiple of 12, where [ ] represents the greatest integer function. we can therefore find 4 integers that are mutiples of 12.

the probability is therefore equal to

4/50 = 2/25, where 4 are the likely outcomes and 50 are the possible outcomes.