Question

A number is selected at random from first 20 natural numbers . Find the probability of the

number being:

(a) a prime number (b) a multiple of 6 (c) an even number

(d) numbers which are divisible both by 4 and 6



Ignore if you don't know the answer, absurd answers will be moderated <3

Answer 1

Answer:

a) 8/20

b) 3/20

c) 10/20

d) 12/20

Step-by-step explanation:

a) there are 8 prime number from 1 to 20 i.e 2,3,5,7,11,13,17,19

b) there are 3 numbers which is divisible 6 i.e 6,12,18

c) there are 10 even number i.e 2,4,6,8,10,12,14,16,18,20

d) the number which divisible both by 4 and 6 is 12 because in multiplication of 4 will find 12 and on 6 u will find 12.