Question

A number is selected at random from first 40 natural numbers. What is the chance that it is a multiple of either 4 or 14?

Answer 1

Answer:

there are 10 chances of coming 4 multiple and 2 chances of 14

Answer 2

The chance that it is a multiple of either 4 or 14 is $\frac{3}{10}$

Given:

A number is selected at random from the first 40 natural numbers.

To Find:

The chance that it is a multiple of either 4 or 14.

Solution:

To find the chance that it is a multiple of either 4 or 14.

As we know,

The total numbers are 40.

So,

n(S) = 40

Now,

The multiples of 4 in the first 40 natural numbers = 4, 8, 12,14,20,24,28, 32, 36, 40

Total 10.

Now,

The multiples of 14 :

14 and 28

Total 2

So,

The chance that it is a multiple of either 4 or 14 is:

$\frac{probability \: of \: getting \: first \: multiples \: of \: 4 + multiples \: of \: 14}{sample \: space} = \frac{10 + 2}{40} = \frac{12}{40} = \frac{3}{10}$

Henceforth, the chance that it is a multiple of either 4 or 14 is

Henceforth, the chance that it is a multiple of either 4 or 14 is $\frac{3}{10}$

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