Math, asked by BrainlyHelper, 1 year ago

A number is selected at random from first 50 natural numbers. Find the probability that it is a multiple of 3 and 4.

Answers

Answered by nikitasingh79
146

SOLUTION :

Given : A number is selected from first 50 natural numbers .

First 50 natural numbers  = {1, 2, 3 …. 50}

Total number of possible outcome = 50

Let E = Event of getting a number which is a multiple of 3 and 4  

Multiples of 3 and 4 are = 12, 24, 36, 48

No. of favorable outcomes = 4

Probability ,P(E) = Number of favourable outcomes / total number of outcomes

P(E) = 4/50 = 2/25  

Hence, the Probability of getting a number which is a multiple of 3 and 4 is 2/25.

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Answered by vignesh3627
45

Answer:

the first 50 rational numbers are 1,2,3........50

Step-by-step explanation:

let E be the event that the probability of getting the multiples of 3 and 4

number of possible outcomes are = 12 24 36 48

total number of outcomes =50

number of outcomes favourable to E= 4

P(E)= 4/50= 2/25

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