Question

A number is selected at random from first 70 natural numbers find the probability that it is multiple of 3 and 4

Answer 1

Total number of outcomes = 70

Multiples of 3 and 4 (12) up to 70 = 70/12 = 5 10/12

No. of multiples of 12 from 1 to 70 = 5

No. of possible outcomes = 5

Probability = 5/70 = 1/14

• I hope it will be helpful to you.

Answer 2

Answer:

12/25

Step-by-step explanation:

Given:

n(s)=1,2,3,....,50

Solution :-

multiple of 3=3,6,9,....,48

number of multiples of 3=16

number of multiples of 4=12

number of multiples of 3 and 4=4

∴n(A)=16+12−4=28−4=24

P(E)= 24/50= 12/25 ANSWER.

Hence, the number of probability that selected number is a multiple of 3 or 4 is 12/25