Question

a number is selected at random from integer 1 to100 find the probability that is a) a perfect square b) no
t a perfect cube
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Answer 1

Answer:

a) No. of perfect square no.s from 1 -100= {1,4,9,16,25,36,49,64,81 and 100}

                                                                  = 10

Probability= $\frac{100}{10}$

                 = $\frac{10}{1}$

∴ The probability of getting a perfect square from 1-100 = $\frac{10}{1}$

b)  No. of perfect cubes from 1-100= {1, 8, 27, 64}

                                                         = 4

Numbers from 1-100 that are not perfect cubes= 100-4

                                                                                     = 96

Probabilty= $\frac{96}{100}$

                = $\frac{24}{25}$

∴ The probability of not getting a perfect cube from 1-100= $\frac{24}{25}$

Hope this helps you.....

Answer 2

Answer:

a) 1/10 b) 24/25

Step-by-step explanation:

n(t)=100

a) Let A be the event of getting a perfect square number

A{1,4,9,16,25,36,49,64,81,100}

n(A)=10

So, P(A)=n(A)/n(t)

P(A)=10/100

P(A)=1/10

b) Let B be the event of getting not a perfect cube

B{1,8,27,64}

for not getting a perfect cube=100-4=96

P(B)=96/100

P(B)=24/25