A number is selected at random from the first 35 natural number.what is the probability that it is either a multiple of 5 or a multiple of 7
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n[s}=35
n{e}= multiple of 5=5,10,15,20,25,30,35=total=7
mutiple of 7= 7,14,21,28,35= total=5
hence n{e}=7+5=12
so p{e}=n{e}/n{s}
12/35
n{e}= multiple of 5=5,10,15,20,25,30,35=total=7
mutiple of 7= 7,14,21,28,35= total=5
hence n{e}=7+5=12
so p{e}=n{e}/n{s}
12/35
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