Question

A number is selected at random from the first 5 natural numbers what is the probability of getting prime number

Answer 1

Answer:

3/5

so please mark me as brainliest

Answer 2

Concept:

We first recall the concept of probability and prime numbers.

Prime numbers are the numbers which are divisible by 1 and themselves.

Probability is a concept that numerically measures the degree of uncertainty and therefore of certainty of the occurrence of an event.

Formula required:

P(E)=No. of outcomes favourable to the occurrence of E divided by the number of all possible outcomes.

=n(E)/n(S)

Given:

We are given the first five natural numbers

To find:

We are to find the probability of selecting a prime number from the first five natural numbers

Solution:

The first five natural numbers are 1,2,3,4,5

So, The sample space, S={1,2,3,4,5}

Let E= event of selecting a prime number from the sample space.

∴n(S)=5

n(E)=3(∵ 1,3 and 5 are the prime numbers)

Thus, the probability of picking a prime number from the set of natural numbers is:

P(E)=n(E)/n(S)

∴ P(E)=3/5

Conclusion:

The probability of selecting a prime number from the first 5 natural numbers is 3/5