Question

A number is selected at random from the numbers 1 to 30.Find the probability that it is a prime number.

Answer 1

Answer:

1/3

Step-by-step explanation:

n(S)= 30

let A be the event of getting prime no.

A= {2,3,5,7,11,13,17,19,23,29}

n(A)= 10

P(A) = n(A)/n(S)

=10/30

=1/3

Answer 2

Step-by-step explanation:

SOLUTION :

Given : A number is selected from 1 to 30

Total number of possible outcome = 30

Let E = Event of getting a prime number

Prime number from 1 to 30  are = 2, 3,5,7, 11,13,17, 19, 23, 29

Number of outcomes  favorable to E = 10

Probability ,P(E) = Number of favourable outcomes / total number of outcomes

P(E) = 10/30 = ⅓  

Hence, the Probability of getting a  prime number from 1 to  30 ,P(E)  is 1/3.

Hope this helps!