A number is selected from the first 20 natural numbers. Find the probability that it would be divisible by 3 or 7?
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2/5
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PROBABILITY
Given :-
First 20 natural numbers (1, 2, 3, 4, ... , 20)
To find :-
Probability that the number will be divisible by 3 or 7.
Solution :-
In order to calculate the probability, let us write down the sample space first.
S = {3,6,7,9,12,14,15,18}
P(E) = No. of possible outcomes / Total no. of outcomes.
P(Number will be divisible by 3 or 7) = 8/20
= 2/5
= 0.4
=> The probability that the number will be divisible by 3 or 7 is 2/5 or 0.4.
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