Question

A number is selected from the numbers 1, 2, 3 , and 4. A second number is selected from the numbers 1,5,6, and 12. Find the probability of the following cases: (a) The sum of two numbers is greater than 7 (b) The product of two numbers is less than 12 (c) The difference between two numbers is divisible by 3 (d) The product of two numbers is a prime number​

Answer 1

Answer:

Number x can be selected in three ways and corresponding to each such way there are three ways of selecting number y. Therefore, two numbers can be selected in 9 ways as listed :

(1,1),(1,4),(1,9),(2,1),(2,4),(2,9),(3,1),(3,4),(3,9)

So, total number of elementary events = 9

The product xy will be less than 9, if x, and y are chosen in one of the following ways :

(1,1),(1,4),(2,1),(2,4),(3,1)

Therefore, favourable number of elementary events = 5

Therefore, required probability =

9

5

Step-by-step explanation:

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