A number is taken at random from the numbers 1 to 100. Find the probability that the number is divisible by i) '3' ii) '7' iii) '3' or '7'
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Answer:
Total number of numbers n(S)=100
Numbers divisible be 4 between 1 to 100 are {4,8,12,16,20,24,28,32,36,40,44,48,52,56,60,64,68,72,76,80,84,88,92,96,100}
Number divisible by 6 between 1 to 100 are {6,12,18,24,30,36,42,48,54,60,66,72,78,84,90,96}
Hence numbers divisible by 4 or 6 between 1 to 100 are {4,6,8,12,16,18,20,24,28,30,32,36,40,42,44,48,52,54,56,60,64,66,68,72,76,78,80,84,88,90,92,96,100}, n(E)=33
Hence the probability that it is divisible by 3 or 7 is
n(S)
n(E)
=
100
33
Step-by-step explanation:
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