Question

a number is three times the sum of its digits find the number​

Answer 1

Answer:

Let the digits at tens be t

and the digits at units place be y

=>10 t + y = 3 ( t + y)

=> 10 t + y = 3t +3y

=> 10-3t + y = 3

=> 7 t + y = 3y

=> 7 t = 3y-y

=>7t = 2y

=> t/y = 2/7

digits at tens = 2 = 2*10 = 20

digits at unit = 7 = 7*1 =7

So, the required answer = 20 + 7 =27

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