Question

) A number less than 100, when divided
by 2,3, 4 and 5 leaves remainder
in I in each case​

Answer 1

Answer:

Let no is x

Div by 3 remainder is 2

x+(3–2)= × +1 is multiple of 3

Div by 4 remainder is 3

x+(4–3) = ×+1 is multiple of 4

Div by 5 remainder is 4

x+(5–4) = x+1 is multiple of 5

So LCM of 3,4,5 is 3×4×5 = 60

Hence x=60–1 =59

59 divided by 7 remainder is 3