A number less than 100 when divided by 9 gives a quotient equal to the digit in the units’ place and the number formed by inverting the digits exceeds the original number by 9, find the number
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Let the digit at tens place be x and at one's place be y .
10x + y = 9y
10x - 8y = 0
therefore , by reverting digits ,
10y + x = 10x + y + 9
x - y = -1
from the two equations , x = 4 and y = 5 .
Ans: 45
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