Question

A number lies between 90 and 100. When it is divided by 7 there is a remainder of 5. Then required number is:


how will it be solved?​

Answer 1

Answer:

let the number be x

so original number = 7x+ 5

the nearest multiple of 7 in this part is 91

we will add 5 to 91 that is equal to 96 .

we should now proof that our answer is correct so 96 ÷ 7 gives 5 as remainder.

hence prooved.

hope it helps :)

thanks !