Question

A number n is chosen from {2, 4, 6 … 48}. The probability that ‘n’ satisfies the equation (2x – 6) (3x + 12) (x – 6) (x – 10) = 0 is

Answer 1

Answer:

answer is 1\7

Step-by-step explanation:

3 6 10 will satisfy therefore

possible outcomes are 3

total outcomes 24

Answer 2

Answer:

Probability that n satisfies the equation(2x-6)(3x+12)(x-6)(x-10)=0 is $\frac{1}{12}$

Step-by-step explanation:

In this question

We have been given that,

A set {2,4,6,.......,48} and a equation(2x-6)(3x+12)(x-6)(x-10)=0

we need to find the Probability that if we choose the number "n" from the set then it must satisfy the given equation.

According to the Question,

2x-6=0 , x=2{which is not in the given set}

3x+12=0 , x=-4{which is not given in the set}

x-6=0 , x=6{which is given in the set}

x-10=0 , x=10{which is given in the set}

Total numbers in the set that will satisfy the given equation will be 2

Now we have to number of terms in the A.P

$a_{n}=a+(n-1)d$

Here, $a_{n}=48$ a=2 d=2

Now putting the values we get

48=2+(n-1)2

46=(n-1)2

23=n-1

n=24

So Probability that number in the set will satisfy the given equation will be

$\frac{2}{24}$

$\frac{1}{12}$

Hence, the probability that if n is choosen from the given set such that n will satisfy the given equation will be$\frac{1}{12}$