A number of 2digits has 3 for its ones digit and sum of digit is 1 upon 7 of the number,itself. What is the number?
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Let the ten’s place digit be x
Unit place digit= 3
Original no.= 10x+3
Sum of units place and tens place digits= 1/7*(10x+3)=10x+3/7
According to the question,
X+3=10x+3/7
So, 7x+21=10x+3
21-3= 10x-7x
18=3x
18/3=x
6=x
So original no.= 10x+3= 63
Unit place digit= 3
Original no.= 10x+3
Sum of units place and tens place digits= 1/7*(10x+3)=10x+3/7
According to the question,
X+3=10x+3/7
So, 7x+21=10x+3
21-3= 10x-7x
18=3x
18/3=x
6=x
So original no.= 10x+3= 63
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