A number of consist of two digits whose sum is 8.If is18 is added to the number its digits are reversed. find the number.
Answers
Answered by
1
let x be unit place
y be tenth place
so , number is 10y+x
x+y = 8 --------( 1 )
if 18 added , number reversed
therefore ,
10y+x + 18 = 10x +y
10x -x -10y +y = 18
9x - 9y =18
x - y = 2 -------- ( 2 )
from 1 and 2 we get
2x = 10
x = 5
y = 3
so number is 35
y be tenth place
so , number is 10y+x
x+y = 8 --------( 1 )
if 18 added , number reversed
therefore ,
10y+x + 18 = 10x +y
10x -x -10y +y = 18
9x - 9y =18
x - y = 2 -------- ( 2 )
from 1 and 2 we get
2x = 10
x = 5
y = 3
so number is 35
pravinsir:
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Answered by
1
let the digit in tenth place x and at ones place y
then no. is 10x+y
atq,
x+y=8
&
10x+y+18=10y+x
it implies,9x-9y=-18
or
x-y=-2
if u solve the equation s
x will come 3 and y will come 5
and therefore the no. is 10x +y=30+5=35
i hope it helped u friend : )
pls mark it as brainliest
then no. is 10x+y
atq,
x+y=8
&
10x+y+18=10y+x
it implies,9x-9y=-18
or
x-y=-2
if u solve the equation s
x will come 3 and y will come 5
and therefore the no. is 10x +y=30+5=35
i hope it helped u friend : )
pls mark it as brainliest
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