Question

a number of consists of two degits whose some is 10. if 18 is subtracted from the number, it's degits are reserved. find the number.

Answer 1

Answer:

Required number is 64

Step-by-step explanation:

GIVEN :

• number consists two digits which sum = 10.
• 18 subtracted from number, digits get reversed.

TO FIND :

we have to find number by the help of given statement.

EXPLANATION :

Let the two digits be x and y where, x is ones and y is tens,

so, number is x +10y.

After reversing this ,

= we get => y+10x

According to the given question :-

x + y = 10 ...........( 1 )

nd,

x+10 - 18 = y+10x

x+10y−y10x = 18

-9x +9y = 18

x - y = -2 ............. ( 2 )

Adding eq.( 1 ) and eq. ( 1 ) =>

x + y + x -y = 10 - 2

=> 2x = 8

=> x = 4

===> putting the value of x in equation ( 1 )

=> 4 + y = 10

=> y = 10-4

=> y = 6

so,

Number =

x + 10y

=> 4 + 10(6)

=> 4 + 60

=> 64

so,

The Number is 64.

Answer 2

Step-by-step explanation:

QUESTION :-

A number of consists of two degits whose some is 10. if 18 is subtracted from the number, it's degits are reserved. find the number.

ANSWER :-

Let one's digit of a two number is x and ten's digits y, then the number is x+10y.

By reversing its digits One's digit =y and ten's digit =x

Then the number is y+10x

As per statement

x+y=10...(1)

And,

x+10y−18=y+10x

x+10y−y10x=18

−9x+9y=18

x−y=−2 (Dividing by −9) ....(2)

Adding (1) and (2), we have

2x=8 or x=4

From (1):4+y=10

y=6

Answer:

Number =x+10y=4+10(6)=64

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