Question

A number of identical blocks each of mass 0.4 kg are placed one above the other. The minimum horizontal
force required to pull the eighth block from the top without disturbing the others is 15 N. if g=10ms-2
the coefficient of static friction between any two blocks is
(a) 0.5
(b) 0.4
(c) 0.3
(d) 0.25​

Answer 1

The value of static friction is 3.75

Explanation:

Fs(max) = μs η

Fs = force of static friction

μs = coefficient of static friction

η = normal force (Greek letter "eta")

Fs(max) = maximum force of static friction

Solution:

Fs(max) = μs mg

μs = Fs(max)/mg

μs  = 15/(0.4)(10)

μs = 15/3.92

μs = 3.75

Hence the value of static friction is 3.75

Learn more about

What is friction ?

https://brainly.in/question/5284566