Math, asked by studentXZY, 1 day ago

A number of the form 8^n, where n is a natural number greater than 1, cannot be divisible by __________.

A. 1

B. 40

C. 64

D. 2^2n

Answers

Answered by lankedarsan
1

Answer:

C

64 is the answer

Step-by-step explanation:

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Answered by amitnrw
1

A number of the form 8ⁿ , where n is a natural number greater than 1, cannot be divisible by 40

Given:

  • A number of the form 8ⁿ
  • n is a natural number greater than 1

To Find:

  • Number by which 8ⁿ is not divisible
  • A. 1
  • B. 40
  • C. 64
  • D. 2²ⁿ

Solution:

"Prime Factorization is finding prime numbers which when multiplied together results in the original number"

Step 1:

Prime factorize 8  and rewrite 8ⁿ

8 = 2 x 2 x 2

8ⁿ = (2 x 2 x 2)ⁿ

Step 2:

Rewrite (2 x 2 x 2)ⁿ  using (a x b)ⁿ = aⁿ x bⁿ   and  xᵃ * xᵇ = xᵃ⁺ᵇ

8ⁿ =  2ⁿ x 2ⁿ x 2ⁿ

=> 8ⁿ = 2ⁿ x 2ⁿ⁺ⁿ

=> 8ⁿ = 2ⁿ x 2²ⁿ

Hence Divisible by 2²ⁿ

Step 3:

Taking n =2 as n is greater than 1

8ⁿ = 8² = 64 hence Divisible by 64

Step 4:

Every natural number is divisible by 1

Hence 8ⁿ  Divisible by 1

Step 5:

Prime factorize 40

40 = 2 x 2 x 2 x 5  

There is a factor 5 in 40 which is not there in 8ⁿ  Hence,

8ⁿ cannot be divisible by 40

So correct option is B) 40

A number of the form 8ⁿ , where n is a natural number greater than 1, cannot be divisible by 40

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