Question

A number of two digit exceed three times
the
sum of the digit by 3. The right hand digit
is the
square of the left hand digit. Find the
number.
Ans. 39​

Answer 1

Step-by-step explanation:

let the first digit is x

second digit is y

we can write xy = 10x+y

and they given x² = y

and also given

xy =3(x+y) +3

10x+y = 3(x+y) +3

we know that x² = y

10x+x²= 3x+3x²+3

2x²-7x+3=0

x=3 (or) 0.5

we take x=3 and y=x²=3²=9

number is 39

Answer 2

Answer:

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