Question

A number of two digits exceeds four times the sum of his digit by 6 and it is increased by 9 on reversing the digts Find the number,

Answer 1

Answer:

26

Step-by-step explanation:

Let the tens place digit = x

Let the ones place digit = y

10(x)+y = 4(x+y)+6

=>10(x)+y-4(x+y) = 6

=>10x +y-4x-4y =6

=>6x-3y=6

=>3(2x-y)=6

=>2x-y = 2

So,

10(y)+x=4(x+y)+9

=>10(y)+x-4(x+y)=9

=>10y+x-4x-4y=9

=>6y-3x = 9

=>3(2y-x)=9

=>2y-x=3

So we get two equations

2x-y=2 and 2y-x =3

thus

2x-y=2 and add 4y-2x=6

we get,

3y=8

=>y=8/3

hence,

2x-8/3=2

=>2x=2+8/3

=>2x = 14/3

=>x= 7/3

Hence the fraction is

10(7/3)+8/3=70/3+8/3=78/3=26

Pls mark this as the  Brainliest answer!!!