Question

a number of two digits has 3 for its unit digit and the sum of digit is 1/7 of the number itself . what is the number​ ?

Answer 1

Answer:

Step-by-step explanation:

Let the number be xy, where x is the 10th digit and y is the unit digit.

⇒y = 3

Now,

       x + y = 1/7(10x + y)

       x + 3 = 1/7(10x + 3)

       7x + 21 = 10x + 3

       10x + 3 = 7x + 21

       10x - 7x = 21 - 3

                3x = 18

                  x = 18/3

                     = 6

Therefore, the number is 63.