A number of two digits is equal to three times the sum of the digits. Also the unit digit is one more than the three times the ten’s digit. Find the number
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Let the tens digit=x
Unit digit=3x+1
Actual no.=10x+3x+1=13x+1
Sum of digits=x+3x+1=4x+1
Three times sum of digits=3(4x+1)=12x+3
ATQ
=>12x+3=13x+1
=>3-1=13x-12x
=>x=2
Actual no.=13x2+1=26+1=27
Unit digit=3x+1
Actual no.=10x+3x+1=13x+1
Sum of digits=x+3x+1=4x+1
Three times sum of digits=3(4x+1)=12x+3
ATQ
=>12x+3=13x+1
=>3-1=13x-12x
=>x=2
Actual no.=13x2+1=26+1=27
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