A number of two digits whose sum is 8. If 8 is subtracted from the number ,the digit interchange their places the number is?
Answers
Correct Question :
- A number of two digits whose sum is 8. If 18 is subtracted from the number ,the digit interchange their places the number is?
Given,
- Sum of two digits number is 8.
- when 18 is subtracted from the number then the digits interchange their place .
To Find,
- The Two Digit Number
Solution,
⇒Suppose the digit at the ten's place be a
And, Suppose the digit at the one's place be b
Therefore,
- Two Digit Number = 10a + b
- Interchange Number = 10b + a
According to the First Condition :-
- Sum of two digits number is 8.
According to the Second Condition :-
- when 18 is subtracted from the number then the digits interchange their place .
(Put the value of b from the First Condition)
Now Put the Value of a in First Condition :-
Therefore ,
☯ Question:
A number of two digits whose sum is 8. If 8 is subtracted from the number ,the digit interchange their places the number is?
☯ Answer:
- Ten's digit = 5
- Unit's digit = 3
- Original number = 53
☯ Explanation:
Let the ten's digit = x
Now, the unit's digit = (8 - x)
Original number = 10x + (8 - x) = 10x + 8 - x = 9x + 8
Interchanged number = 10(8 - x) + x = 80 - 10x + x = 80 - 9x
★ According To The Question:
9x + 8 - 8 = 80 - 9x
9x + 9x = 80 - 9x
18x = 80
x = 80/18
x = 5
★ Now:
Unit's digit = (8 - x) = (8 - 5) = 3
★ Final Answer:
The number : We will put the value of x in 10x + (8 - x) :-
10(5) + (8 - 5)
50 + 3
53
____________________________