Math, asked by aqeelakhanam, 10 months ago

A number of two digits whose sum is 8. If 8 is subtracted from the number ,the digit interchange their places the number is?

Answers

Answered by vikram991
14

Correct Question :

  • A number of two digits whose sum is 8. If 18 is subtracted from the number ,the digit interchange their places the number is?

\rule{200}1

Given,

  • Sum of two digits number is 8.
  • when 18 is subtracted from the number then the digits interchange their place .

To Find,

  • The Two Digit Number

Solution,

⇒Suppose the digit at the ten's place be a

And, Suppose the digit at the one's place be b

Therefore,

  • Two Digit Number = 10a + b
  • Interchange Number = 10b + a

According to the First Condition :-

  • Sum of two digits number is 8.

\implies \sf{a + b = 8}

\implies \boxed{\sf{b = 8 - a}}

According to the Second Condition :-

  • when 18 is subtracted from the number then the digits interchange their place .

\implies \sf{10a + b - 18 = 10b + a}

\implies \sf{10a - a = 10b - b + 18}

\implies \sf{9a = 9b + 18}

\implies \sf{9a = 9(8 - a) + 18 }

(Put the value of b from the First Condition)

\implies \sf{9a = 72 - 9a + 18}

\implies \sf{9a + 9a = 90}

\implies \sf{18a = 90}

\implies \sf{a = \dfrac{90}{18}}

\implies \boxed{\sf{ a = 5}}

Now Put the Value of a in First Condition :-

\implies \sf{b = 8 - a}

\implies \sf{b = 8 - 5}

\implies \boxed{\sf{b = 3}}

Therefore ,

\large{\boxed{\bold{Two \ Digit \ number :=\:10x+y\:=\:10(5)+3=50+3=53}}}

\rule{200}2

Answered by MissKalliste
10

Question:

A number of two digits whose sum is 8. If 8 is subtracted from the number ,the digit interchange their places the number is?

Answer:

  • Ten's digit = 5
  • Unit's digit = 3
  • Original number = 53

Explanation:

\leadstoLet the ten's digit = x

\leadstoNow, the unit's digit = (8 - x)

\mapstoOriginal number = 10x + (8 - x) = 10x + 8 - x = 9x + 8

\mapstoInterchanged number = 10(8 - x) + x = 80 - 10x + x = 80 - 9x

According To The Question:

\leadsto9x + 8 - 8 = 80 - 9x

\leadsto9x + 9x = 80 - 9x

\leadsto18x = 80

\leadstox = 80/18

\bold\mapstox = 5

Now:

\mapstoUnit's digit = (8 - x) = (8 - 5) = 3

Final Answer:

\longrightarrowThe number : We will put the value of x in 10x + (8 - x) :-

\leadsto10(5) + (8 - 5)

\leadsto50 + 3

\bold\mapsto53

____________________________

Similar questions