Question

A number plus two thirds of itself, plus one half of itself, plus one seventh of itself equals to 97. find the number. ​

Answer 1

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a number plus two third of itself

12%2F3x = 5%2F3x

:

plus one half of itself

+ 1%2F2x

:

plus one seventh of itself

+ 1%2F7x

:

equal 97.

5%2F3x + 1%2F2x + 1%2F7x = 97

:

find the no.

:

A multiple of all 3 denominators is 42:

42*5%2F3x + 42*1%2F2x + 42*1%2F7x = 42(97)

:

CAncel out the denominators:

14(5x) + 21x + 6x = 4074

:

70x + 21x + 6x = 4074

:

97x = 4074

:

x = 4074/97

:

x = 42

$\boxed{Hope\:This\:Helps}$

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