A number series starts with the number -8 and we get the next number by multiplying the previous number by -1 then adding 3. What is the number in the hundredth order?
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11
Step-by-step explanation:
lets say, a(1) = -8
given, a(i) = -a(i-1) + 3
therefore, a(i) = -[-a(i-2)+3]+3 = a(i-2)= ... = a(2) = -a(1)+3 = 8+3 =11
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