Question

a number such that six-sevenths of it shall exceeds four-fifths of it by 2 the number is ​

Answer 1

Answer :

The number is 35.

Explanation :

If we assume the number as $x$

We can say that,

sixth-seventh of $x$ exceeds four-fifths of $x$ by 2.

Given,

$\implies \dfrac{6}{7} {\sf{of}} \: x - \dfrac{4}{5} \: {\sf{of}} \: x = 2$

Solving for $x$ :

$\implies \dfrac{6x}{7} - \dfrac{4x}{5} = 2$

$\implies \dfrac{30x - 28x}{35} = 2$

$\implies \dfrac{2x}{35} = 2$

$\implies 2x = 70$

$\implies x = \dfrac{70}{2}$

$\implies x = \bf 35$

$\therefore {\underline{\bf{The \: number \: is \: 35}}}$

Check point :

We got the number as 35

So,

$\dfrac{6}{7}$ of 35 must exceed $\dfrac{4}{5}$ of it by 2 (given)

Or,

$\to \dfrac{6}{7} {\sf{of}} \: 35 = 30$

And also,

$\to \dfrac{4}{5} {\sf{of}} \: 35 = 28$

Clearly, we can see that 30 exceeds 28 by 2.

Hence, proved ${\boxed{\green{\checkmark{}}}}$

Answer 2

Answer:

answer is 35

Step-by-step explanation:

6x7-4x/5=?

30x-28x/35=?

2x/35=2

2x=70

x=35