Question

A NUMBER THAT CAN BE DIVIDED BY 6 , 9 AND 12 BUT LEAVE A REMAINDER OF ONE

Answer 1

Answer:

Step-by-step explanation:The solution is simple. I add some explanation just for better understanding.

Let the number be x. Since x leaves remainder 1 when divided by 6,7,8,9 and 12, x can be written as

x=6a+1=7b+1=8c+1=9d+1=12e+1 for integers a,b,c,d and e.

Therefore,

x−1=6a=7b=8c=9d=12e.

This mean x−1 is common multiple of 6,7,8,9 and 12. The least common multiple of 6,7,8,9 and 12 is the least value of x−1 which is 504. The other multiples are 1008, 1512 etc. Accordingly, the least value of x is 505. The other values are 1009,1513 etc.

Answer 2

6 will divide by 5 , 9 divide by 4 and 12 will divide by 11