a number twice of which decreased by 7 gives 55
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Twice of 31 decreased by 7 gives 55
Given : A number twice of which decreased by 7 gives 55
To Find : The number
Solution:
Assume that Number is N
Twice of Number = 2N
Decreased by 7 Hence 2N - 7
Gives 55
Hence Equate with 55
=> 2N - 7 = 55
=> 2N = 55 + 7
=> 2N = 62
=> N = 31
Hence twice of 31 decreased by 7 gives 55
Learn More:
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