Question

A number was divided succesaively in order by 4 '5 and 6 the reminders where respectively 2 '3 and 4.​

Answer 1

Answer:

$\blue{Let \: p \: be \: the \: number. }\\\blue{\underline{Suppose,}} \\\blue{ p÷4=q,remainder=2 }\\ \blue{q÷5=r, remainder=3} \\ \blue{r÷6=s, remainder=4 }\\ \blue{Then,} \\ \blue{r=6s+4} \\ \blue{q=5r+3=5(6s+4)+3=30s+23 }\\ \blue{p=4q+2=4(30s+23)+2=120s+94} \\ \blue{Let \: us \: now \: assume \: that \: the \: remainder \: s=1. }\\\blue{ Then \: we \: have: }\\\blue{ p=(120×1)+94=214 }\\ \blue{Hence, \: the \: number \: is 214} \\ \\ \red{\mathfrak{\underline{\large{Hope \: It \: Helps \: You }}}} \\ \green{\mathfrak{\underline{\large{Mark \: Me \: Brainliest}}}}$