Question

A number when divided 41 and 68 leaves as the remainder what is the number

Answer 1

✰AnSwer:

• The number is 9.

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✒ GiVen:

• A number when divided 41 and 68 leaves as the remainder 5.

✒ To Find:

• The original number = ?

✒ SoluTion:

Let us subtract 5 by these 2 numbers as we need to take the factors of the given numbers.

➔41- 5

➔36

➔2 × 2 × 3 × 3

Similarly for the other number,

➔68 - 5

➔63

➔3 × 3 × 7

Now,

• HCF(36,68) = 3 × 3 = 9

So, your original number is 9.

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Answer 2

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✤ A number when divided 41 and 68 leaves 5 as the remainder . What is the number ?

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✤ Subtract the remainder from the given numbers .

☯ 41 - 5 = 36

☯ 68 - 5 = 63

✤ Factorise the numbers obtained .

☯ 36 = 2×2×3×3

☯ 63 = 3×3×7

✤ Now , take HCF .

☯ HCF = 3×3 = 9

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⚡The number is 9 .

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