Question

A number when divided by 143 leaves 31 as a remainder. What will be remainder when the same number is divided by 13.

Answer 1

N = 143x +31
Now N/13
= 143x + 31/13
= 0*x + 5/13
= 0+5/13
= 5/13
= 5 remainder

Or

Just have a glimpse on the no. 143
We can say that its divisible by 13 
So remain part is 31
31/13 gives 5 as remainder

Answer 2

We know that,
Dividend = divisior x quoitent + remainder.

Given : Divisor = 143.
Remainder = 13.
So, the given no N will be,
N = 143x + 13.
( where x = quotient )

therefore, 143x + 13
➡ 13 ( 11x ) + ( 13 * 2 + 5 )
➡ 13 ( 11x + 2) + 5 ........( taking 13 as common.)
➡ 13 ( 11x + 2 ) + 5

When this no is divided by 13, remainder will be 5.

Hope it will help you !!!