Question

A number when divided by 145 leaves a remainder 39 what will be remainder when original number is divided by 29

Answer 1

Hey



Let the number be x .


It is divided by 145

And ,

leaves remainder = 39


Let quotient be q .


So ,


x = 145 q + 39


x = 29 * 5 * q + 29 * 1 + 10


x = 29 ( 5q + 1 ) + 10


Here by this equation ,

it is clear that x is divided by 29 .

Quotient is ( 5q + 1 )


And ,

remainder is = 10


So ,


required remainder = 10


thanks :)