Question

a number when divided by 45 leaves remainder 30. if the number is divided by 5 the remainder must be

Answer 1

Let’s assume a number is 75
75 is divide by 45 den remainder is 30 and

That same number 75 is divide by 5 den it is remainder is 00

It is trial & error method

Answer 2

hye

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let the number be x

=>A number when divided by 45 leaves remainder 30.  

let the quoteint be 10

=>  x / 45 = remainder = 30

x = 45 *qoutient +30

=> 45 *10 +30

=>x = 470

if the number is divided by 5 then the  remainder must be

=> 0 as w.k.t 45 is divisible by 5

so whatever the number might be the remainder when 5 is divide , the anser is 0

check

let the quotient be 11

=>45 *11 +30

=>525

=>525/5 = remander = 0 

=>if quoteint is 99

=>45 *99 +30

=> 4485

so whatever the number might be ,the remainder by  when 5 is divided , the remaninder is  0

= 4485/5 = remainder is 0