Question

A number when divided by 5 gives 0 as remainder, that number when divided by 7 gives 0 as remainder also. What will be the remainder when that number is divided by 35?

Answer 1

The correct answer is the remainder is 0 when that number is divided by 35.

• It has to be a multiple of 7, 14, 21, and 28 are the multiples of 7 as a result, every second multiple leftover after 14 will equal 0. Thus, the remainder for other multiples will always be 7.
• It has to be a multiple of 5, 10, 15, and 20 are the multiples of 5 as a result, every second multiple leftover after 10 will equal 0. Thus, the remainder for other multiples will always be 5.
• LCM of 5 and 7 is 35 thus the remainder will be 0 since the number is multiple of 5 and 7.

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Answer 2

The remainder will be 0 when the number is divided by 35

Given :

A number when divided by 5 gives 0 as remainder, that number when divided by 7 gives 0 as remainder also

To find :

The remainder when that number is divided by 35

Solution :

Step 1 of 2 :

Write down the given data

A number when divided by 5 gives 0 as remainder

So the number is completely divisible by 5

Also the number when divided by 7 gives 0 as remainder

So the number is completely divisible by 7

Step 2 of 2 :

Find the remainder when that number is divided by 35

The number is completely divisible by 5 and 7

Now 5 and 7 are prime numbers

LCM of 5 and 7 = 35

So the number is completely divisible by 35

Hence the remainder will be 0 when the number is divided by 35

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