Question

a number when divided by 6,7,8 leaves 3,4,5 as remainder respectively

Answer 1

Answer:

3

Step-by-step explanation:

ans is 3

Answer 2

As a successive division takes place. Then considering the later’s divisive status will bring for a divisor 7,the quotient as m the dividend is (7m+6). So, in case of primary division the number will be 6×(7m+6)+3,as the divisor here to be 6, quotient is (7m+6) and remainder 3. So number N= 6(7m+6)+3= 42m+36+3=42m+39. Then after division by 7 yields 7(6m+5)+4 =42m+39. Here quotient (6m+5) and remainder 4. In successive division by 6 ie for division of (6m+5) by 6 will leave remainder 5. Hence successive remainders would be 4 & 5 respectively.

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