A number when divided by 627 leaves a remainder 43. by dividing the same number by 19, the remainder will be?
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Answered by
13
let A be the number which is divided by 627 and on on dividing the number we get q as the quotient,
now we have to apply here,
dividend=divisor×quotient+remainder,
A=627×q+43,
so now you have to break the remainder in terms of 19,
then
A=19×33q+19×2+5,
since here 19×33q and 19×2 is exactly divisible by 19 so 5 will be the remainder ....
now we have to apply here,
dividend=divisor×quotient+remainder,
A=627×q+43,
so now you have to break the remainder in terms of 19,
then
A=19×33q+19×2+5,
since here 19×33q and 19×2 is exactly divisible by 19 so 5 will be the remainder ....
sonam3382:
ya i know hindi...
Answered by
6
Let the number is y.
when it is divided by 627 , the remainder is 43.
Let 627 was multiplied with x.
so we can write y as follows.....
y= 627x + 43
y=19×33x + 43
y = 19×33x + 19×2 + 5
y= 19(33x+2) +5
So when y is devided by 19 , the remainder is 5 and 19 is multiplied with 33x+2
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