Question

A number when divided by 779 gives a remainder 47.By dividing the same number by 19, what would be the remainder

Answer 1

Hey

Let the number be A = 779X + 47
=> A = 19(41X) + 19(2) + 9
=> A = 19 [ 41X + 2 ] + 9

Hence, when the number is divided by 19, the quotient is (41X + 2) and the remainder is 9 ✓✓

We use Euclid's Lemma to Write the above Conclusion ✓✓

Answer 2

We must recall that:

In mathematics, the remainder is the amount "left over" after performing some computation. In arithmetic, the remainder is the integer "left over" after dividing one integer by another to produce an integer quotient.

Number:- $(779\times x)+47$

where $x$ is the quotient

$=(19\times 41\times a)+(19\times 2)+9$

$=19(41a+2)+9$

$=$ ∴ Required remainder $=9.$

Answer 3

The remainder is 9.

Given:

Remainder = 47

Divisor = 779

Dividend = 19

To Find:

Remained

Formula Used:

Euclid's Lemma

Step-by-step explanation:

Let the number be A = 779X + 47

Number = (779 x a) + 47 where "a" resembles the quotient

= (19x41 xa) + (19x2) + 9

= 19x(41a + 2) + 9

= 19x(New quotient) + 9

Required remainder = 9

Therefore, when the number is divided by 19, the quotient will be (41X + 2) and the remainder will be 9