Question

A number when divided by a divisor leaves a
remainder of 24, when twice the original
number is divided by the same divisor the
remainder is 11, then divisor is -
(1) 13 (2) 59
(3) 35 (4) 37

Answer 1

Hey

Here is your answer,

Let the original number be 'a'.
Let the divisor be 'd'.
Let the quotient of dividing 'a' by 'd' be 'x'.
Therefore, we can write the division as \\frac{a}{d}\\) = x and the remainder is 24.
i.e., a = dx + 24

Twice the original number is divided by d means 2a is divided by d.
We know that a = dx + 24.
Therefore, 2a = 2(dx + 48) or 2a = 2dx + 48

When (2dx + 48) is divided by 'd' the remainder is 11.
2dx is divisible by 'd' and will therefore, not leave a remainder.

The remainder of 11 would be the remainder of dividing 48 by d.

When 37 divides 48, the remainder is 11.

The answer is option (4)

Hope it helps you!

Answer 2

Answer:

Let the original number be 'a'.

Let the divisor be 'd'.

Let the quotient of dividing 'a' by 'd' be 'x'.

Since the remainder is 24 and we know the relation between Divisor, Dividend, Quotient, and Remainder -                                                                            (i.e Dividend=Divisor x quotient+remainder).

, a = dx + 24

Twice the original number is divided by d means 2a is divided by d.

We know that a = dx + 24.

Therefore, 2a = 2 ( dx + 24 ) or 2a = 2dx + 48

When (2dx + 48) is divided by 'd' the remainder is 11.

2dx is divisible by 'd' and will therefore, not leave a remainder.

The remainder of 11 would be the remainder of dividing 48 by d.

When 37 divides 48, the remainder is 11.

Step-by-step explanation: