Question

A number when divided by a divisor leaves a
remainder of 25. When twice the original
number is divided by the same divisor, the
remainder is 11. What is the value of the
divisor?​

Answer 1

Answer:

the right way to do:

n=m*x+24, and

2n=p*x+11

therefore, 2mx+48=px+11

x is an integer

therefore x=37 or x=1

Answer 2

Answer:

• The value of the divisor is 39.

Given:

• A number when divided by a divisor leaves a remainder 25.

• If the twice of the original number is divided by the same divisor then the remainder is 11.

To find:

• The divisor.

Solution:

Let A be the divided D and Q be the quotient and R be the remainder.

=> Divided = Divisor × Quotient + Remainder

=> A = D × Q + 25

If we, make the Divided twice the Quotient and remainder will also be double.

=> 2A = D × 2Q + 50

But according to the given condition it leaves the Remainder is 11.

Note: Divisor is always greater than 25.

Here, we can have only one number bigger than 25 since 2(25) = 50. Also given it leaves remainder

Let that number be x.

=> x = 50 - 11

=> x = 39

Therefore,

=> 2A = D × (2Q + 1) + 11

Quotient increases by one when 39 is divided by Divisor.

Hence, the value of the divisor is 39.